Oracle 1Z1-051 시험문제

IT자격증을 많이 취득하여 IT업계에서 자신만의 단단한 자리를 보장하는것이 여러분들의 로망이 아닐가 싶습니다. ITExamDump의 완벽한 Oracle인증 1Z1-051덤프는 IT전문가들이 자신만의 노하우와 경험으로 실제Oracle인증 1Z1-051시험문제에 대비하여 연구제작한 완벽한 작품으로서 100%시험통과율을 보장합니다.

여러분이 다른 사이트에서도Oracle인증1Z1-051시험 관련덤프자료를 보셨을 것입니다 하지만 우리ITExamDump의 자료만의 최고의 전문가들이 만들어낸 제일 전면적이고 또 최신 업데이트일 것입니다.우리덤프의 문제와 답으로 여러분은 꼭 한번에Oracle인증1Z1-051시험을 패스하실 수 있습니다.

시험 번호/코드: 1Z1-051
시험 이름: Oracle (Oracle Database: SQL Fundamentals I)

Oracle인증1Z1-051시험덤프공부자료는ITExamDump제품으로 가시면 자격증취득이 쉬워집니다. ITExamDump에서 출시한 Oracle인증1Z1-051덤프는 이미 사용한 분들에게 많은 호평을 받아왔습니다. 시험적중율 최고에 많은 공부가 되었다고 희소식을 전해올때마다 ITExamDump는 더욱 완벽한Oracle인증1Z1-051시험덤프공부자료로 수정하고기 위해 최선을 다해왔습니다. 최고품질으Oracle인증1Z1-051덤프공부자료는ITExamDump에서만 찾아볼수 있습니다.

ITExamDump는 많은 분들이Oracle인증1Z1-051시험을 응시하여 성공하도록 도와주는 사이트입니다ITExamDump의 Oracle인증1Z1-051 학습가이드는 시험의 예상문제로 만들어진 아주 퍼펙트한 시험자료입니다. Oracle인증1Z1-051시험은 최근 가장 인기있는 시험으로 IT인사들의 사랑을 독차지하고 있으며 국제적으로 인정해주는 시험이라 어느 나라에서 근무하나 제한이 없습니다. ITExamDump로 여러분은 소유하고 싶은 인증서를 빠른 시일내에 얻게 될것입니다.

Oracle인증 1Z1-051시험취득 의향이 있는 분이 이 글을 보게 될것이라 믿고ITExamDump에서 출시한 Oracle인증 1Z1-051덤프를 강추합니다. ITExamDump의Oracle인증 1Z1-051덤프는 최강 적중율을 자랑하고 있어 시험패스율이 가장 높은 덤프자료로서 뜨거운 인기를 누리고 있습니다. IT인증시험을 패스하여 자격증을 취득하려는 분은ITExamDump제품에 주목해주세요.

현재 많은 IT인사들이 같은 생각하고 잇습니다. 그것은 바로Oracle 1Z1-051인증시험자격증 취득으로 하여 IT업계의 아주 중요한 한걸음이라고 말입니다.그만큼Oracle 1Z1-051인증시험의 인기는 말 그대로 하늘을 찌르고 잇습니다,

1Z1-051 덤프무료샘플다운로드하기: http://www.itexamdump.com/1Z1-051.html

NO.1 Examine the structure of the SHIPMENTS table:
name Null Type
PO_ID NOT NULL NUMBER(3)
PO_DATE NOT NULL DATE
SHIPMENT_DATE NOT NULL DATE
SHIPMENT_MODE VARCHAR2(30)
SHIPMENT_COST NUMBER(8,2)
You want to generate a report that displays the PO_ID and the penalty amount to be paid if the
SHIPMENT_DATE is later than one month from the PO_DATE. The penalty is $20 per day.
Evaluate the following two queries:
SQL> SELECT po_id, CASE
WHEN MONTHS_BETWEEN (shipment_date,po_date)>1 THEN
TO_CHAR((shipment_date - po_date) * 20) ELSE 'No Penalty' END PENALTY
FROM shipments;
SQL>SELECT po_id, DECODE
(MONTHS_BETWEEN (po_date,shipment_date)>1,
TO_CHAR((shipment_date - po_date) * 20), 'No Penalty') PENALTY
FROM shipments;
Which statement is true regarding the above commands?
A. Both execute successfully and give correct results.
B. Only the first query executes successfully but gives a wrong result.
C. Only the first query executes successfully and gives the correct result.
D. Only the second query executes successfully but gives a wrong result.
E. Only the second query executes successfully and gives the correct result.
Answer: C

Oracle인증   1Z1-051   1Z1-051시험문제

NO.2 Which two statements are true regarding single row functions? (Choose two.)
A. They a ccept only a single argument.
B. They c an be nested only to two levels.
C. Arguments can only be column values or constants.
D. They a lways return a single result row for every row of a queried table.
E. They c an return a data type value different from the one that is referenced.
Answer: DE

Oracle자격증   1Z1-051덤프   1Z1-051최신덤프

NO.3 You need to extract details of those products in the SALES table where the PROD_ID column
contains the string '_D123'.
Which WHERE clause could be used in the SELECT statement to get the required output?
A. WHERE prod_id LIKE '%_D123%' ESCAPE '_'
B. WHERE prod_id LIKE '%\_D123%' ESCAPE '\'
C. WHERE prod_id LIKE '%_D123%' ESCAPE '%_'
D. WHERE prod_id LIKE '%\_D123%' ESCAPE '\_'
Answer: B

Oracle최신덤프   1Z1-051   1Z1-051기출문제   1Z1-051   1Z1-051   1Z1-051 dumps

NO.4 You need to produce a report where each customer's credit limit has been incremented by $1000. In
the output, t he customer's last name should have the heading Name and the incremented credit limit
should be labeled New Credit Limit. The column headings should have only the first letter of each word in
uppercase .
Which statement would accomplish this requirement?
A. SELECT cust_last_name Name, cust_credit_limit + 1000
"New Credit Limit"
FROM customers;
B. SELECT cust_last_name AS Name, cust_credit_limit + 1000
AS New Credit Limit
FROM customers;
C. SELECT cust_last_name AS "Name", cust_credit_limit + 1000
AS "New Credit Limit"
FROM customers;
D. SELECT INITCAP(cust_last_name) "Name", cust_credit_limit + 1000
INITCAP("NEW CREDIT LIMIT")
FROM customers;
Answer: C

Oracle자격증   1Z1-051   1Z1-051   1Z1-051최신덤프   1Z1-051

NO.5 Evaluate the following query:
SELECT INTERVAL '300' MONTH,
INTERVAL '54-2' YEAR TO MONTH,
INTERVAL '11:12:10.1234567' HOUR TO SECOND
FROM dual;
What is the correct output of the above query?
A. +25-00 , +54-02, +00 11:12:10.123457
B. +00-300, +54-02, +00 11:12:10.123457
C. +25-00 , +00-650, +00 11:12:10.123457
D. +00-300 , +00-650, +00 11:12:10.123457
Answer: A

Oracle자격증   1Z1-051   1Z1-051

NO.6 Evaluate the following query:
SQL> SELECT promo_name q'{'s start date was }' promo_begin_date
AS "Promotion Launches"
FROM promotions;
What would be the outcome of the above query?
A. It produces an error because flower braces have been used.
B. It produces an error because the data types are not matching.
C. It executes successfully and introduces an 's at the end of each promo_name in the output.
D. It executes successfully and displays the literal " {'s start date was } " for each row in the output.
Answer: C

Oracle자격증   1Z1-051 dumps   1Z1-051 dumps

NO.7 Which SQL statements would display the value 1890.55 as $1,890.55? (Choose three .)
A. SELECT TO_CHAR(1890.55,'$0G000D00')
FROM DUAL;
B. SELECT TO_CHAR(1890.55,'$9,999V99')
FROM DUAL;
C. SELECT TO_CHAR(1890.55,'$99,999D99')
FROM DUAL;
D. SELECT TO_CHAR(1890.55,'$99G999D00')
FROM DUAL;
E. SELECT TO_CHAR(1890.55,'$99G999D99')
FROM DUAL;
Answer: ADE

Oracle자격증   1Z1-051 pdf   1Z1-051   1Z1-051인증

NO.8 View the Exhibit to examine the description for the SALES table.
Which views can have all DML operations performed on it? (Choose all that apply.)
A. CREATE VIEW v3
AS SELECT * FROM SALES
WHERE cust_id = 2034
WITH CHECK OPTION;
B. CREATE VIEW v1
AS SELECT * FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
C. CREATE VIEW v2
AS SELECT prod_id, cust_id, time_id FROM SALES
WHERE time_id <= SYSDATE - 2*365
WITH CHECK OPTION;
D. CREATE VIEW v4
AS SELECT prod_id, cust_id, SUM(quantity_sold) FROM SALES
WHERE time_id <= SYSDATE - 2*365
GROUP BY prod_id, cust_id
WITH CHECK OPTION;
Answer: AB

Oracle자료   1Z1-051자료   1Z1-051   1Z1-051최신덤프   1Z1-051인증   1Z1-051자료

NO.9 View the Exhibit and examine the structure of the PRODUCTS table.
All products have a list price.
You issue the following command to display the total price of each product after a discount of 25% and a
tax of 15% are applied on it. Freight charges of $100 have to be applied to all the products.
SQL>SELECT prod_name, prod_list_price -(prod_list_price*(25/100))
+(prod_list_price -(prod_list_price*(25/100))*(15/100))+100
AS "TOTAL PRICE"
FROM products;
What would be the outcome if all the parenthese s are removed from the above statement?
A. It produces a syntax error.
B. The result remains unchanged.
C. The total price value would be lower than the correct value.
D. The total price value would be higher than the correct value.
Answer: B

Oracle pdf   1Z1-051   1Z1-051 pdf   1Z1-051시험문제

NO.10 View the Exhibit and examine the data in the CUSTOMERS table.
Evaluate the following query:
SQL> SELECT cust_name AS "NAME", cust_credit_limit/2 AS MIDPOINT,MIDPOINT+100 AS "MAX
LOWER LIMIT"
FROM customers;
The above query produces an error on execution.
What is the reason for the error?
A. An alias cannot be used in an expression.
B. The a lias NAME should not be enclosed with in double quotation marks .
C. The MIDPOINT+100 expression gives an error because CUST_CREDIT_LIMIT contains NULL
values.
D. The a lias MIDPOINT should be enclosed with in double quotation marks for the
CUST_CREDIT_LIMIT/2 expression .
Answer: A

Oracle   1Z1-051 dump   1Z1-051

NO.11 Using the CUSTOMERS table, you need to generate a report that shows 50% of each credit
amount in each income level. The report should NOT show any repeated credit amounts in each income
level.
Which query would give the required result?
A. SELECT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
B. SELECT DISTINCT cust_income_level, DISTINCT cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
C. SELECT DISTINCT cust_income_level ' ' cust_credit_limit * 0.50
AS "50% Credit Limit"
FROM customers;
D. SELECT cust_income_level ' ' cust_credit_limit * 0.50 AS "50% Credit Limit"
FROM customers;
Answer: C

Oracle   1Z1-051시험문제   1Z1-051 pdf   1Z1-051

NO.12 Examine the structure of the PROMOTIONS table:
name Null Type
PROMO_ID NOT NULL NUMBER(6)
PROMO_NAME NOT NULL VARCHAR2(30)
PROMO_CATEGORY NOT NULL VARCHAR2(30)
PROMO_COST NOT NULL NUMBER(10,2)
The management wants to see a report of unique promotion costs in each promotion category.
Which query would achieve the required result?
A. SELECT DISTINCT promo_cost, promo_category FROM promotions;
B. SELECT promo_category, DISTINCT promo_cost FROM promotions;
C. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
D. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer: D

Oracle dumps   1Z1-051   1Z1-051   1Z1-051시험문제

NO.13 View the Exhibit; e xamine the structure of the PROMOTIONS table.
Each promotion has a duration of at least seven days .
Your manager has asked you to generate a report, which provides the weekly cost for each promotion
done to l date.
Which query would achieve the required result?
A. SELECT promo_name, promo_cost/promo_end_date-promo_begin_date/7
FROM promotions;
B. SELECT promo_name,(promo_cost/promo_end_date-promo_begin_date)/7
FROM promotions;
C. SELECT promo_name, promo_cost/(promo_end_date-promo_begin_date/7)
FROM promotions;
D. SELECT promo_name, promo_cost/((promo_end_date-promo_begin_date)/7)
FROM promotions;
Answer: D

Oracle   1Z1-051최신덤프   1Z1-051덤프   1Z1-051기출문제

NO.14 View the Exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
A. listing of customers who do not have a credit limit and were born before 1980
B. finding the number of customers, in each city, whose marital status is 'married'
C. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
D. listing of those customers whose credit limit is the same as the credit limit of customers residing in the
city 'Tokyo'
E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of
all the customers
Answer: DE

Oracle dumps   1Z1-051   1Z1-051   1Z1-051   1Z1-051기출문제   1Z1-051자료

NO.15 Which statement is true regarding the INTERSECT operator?
A. It ignores NULL values.
B. Reversing the order of the intersected tables alters the result.
C. The names of columns in all SELECT statements must be identical.
D. The number of columns and data types must be identical for all SELECT statements in the query.
Answer: D

Oracle인증   1Z1-051   1Z1-051 dump   1Z1-051

NO.16 Which two statements are true regarding the USING and ON clauses in table joins? (Choose two.)
A. Both USING and ON clauses can be used for equijoins and nonequijoins.
B. A maximum of one pair of columns can be joined between two tables using the ON clause.
C. The ON clause can be used to join tables on columns that have different names but compatible data
types.
D. The WHERE clause can be used to apply additional conditions in SELECT statements containing the
ON or the USING clause.
Answer: CD

Oracle dump   1Z1-051자료   1Z1-051   1Z1-051최신덤프   1Z1-051자격증

NO.17 View the Exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS, and TIMES
tables.
The PROD_ID column is the foreign key in the SALES table, which references the PRODUCTS table.
Similarly, the CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Evaluate the following CREATE TABLE command:
CREATE TABLE new_sales(prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true regarding the above command?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the
column definition.
B. The NEW_SALES table would get created and all the NOT NULL constraints defined on the specified
columns would be passed to the new table.
C. The NEW_SALES table would not get created because the column names in the CREATE TABLE
command and the SELECT clause do not match.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the
specified columns would be passed to the new table.
Answer: B

Oracle   1Z1-051   1Z1-051   1Z1-051

NO.18 View the Exhibit and examine the structure of the PRODUCTS table.
You need to generate a report in the following format:
CATEGORIES
5MP Digital Photo Camera's category is Photo
Y Box's category is Electronics
Envoy Ambassador's category is Hardware
Which two queries would give the required output? (Choose two.)
A. SELECT prod_name q'''s category is ' prod_category CATEGORIES
FROM products;
B. SELECT prod_name q'['s ]'category is ' prod_category CATEGORIES
FROM products;
C. SELECT prod_name q'\'s\' ' category is ' prod_category CATEGORIES
FROM products;
D. SELECT prod_name q'<'s >' 'category is ' prod_category CATEGORIES
FROM products;
Answer: CD

Oracle   1Z1-051   1Z1-051 dumps   1Z1-051시험문제

NO.19 View the E xhibit and examine the data in the EMPLOYEES table.
You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:
SQL>SELECT ename ' joined on ' hiredate
', the total compensation paid is '
TO_CHAR(ROUND(ROUND(SYSDATE-hiredate)/365) * sal + comm)
"COMPENSATION UNTIL DATE"
FROM employees;
What is the outcome?
A. It generates an error because the alias is not valid.
B. It executes successfully and gives the correct output.
C. It executes successfully but does not give the correct output.
D. It generates an error because the usage of the ROUND function in the expression is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.
Answer: C

Oracle자료   1Z1-051   1Z1-051   1Z1-051   1Z1-051자료

NO.20 Which three statements are true regarding the data types in Oracle Database 10g/11g? (Choose
three.)
A. Only one LONG column can be used per table.
B. A TIMESTAMP data type column stores only time values with fractional seconds.
C. The BLOB data type column is used to store binary data in an operating system file.
D. The minimum column width that can be specified for a VARCHAR2 data type column is one.
E. The value for a CHAR data type column is blank-padded to the maximum defined column width.
Answer: ADE

Oracle기출문제   1Z1-051최신덤프   1Z1-051자격증   1Z1-051

ITExamDump는 여러분이 빠른 시일 내에Oracle 1Z1-051인증시험을 효과적으로 터득할 수 있는 사이트입니다.Oracle 1Z1-051인증 자격증은 일상생활에 많은 개변을 가져올 수 있는 시험입니다.Oracle 1Z1-051인증 자격증을 소지한 자들은 당연히 없는 자들보다 연봉이 더 높을 거고 승진기회도 많아지며 IT업계에서의 발전도 무궁무진합니다.